What is the value of the variable in the equation 5y + 2 = 17?

Prepare for the ASVAB MEPS Entrance Exam with engaging study tools and multiple-choice questions. Each question offers comprehensive hints and explanations, ensuring you're ready for your exam day with confidence.

To determine the value of the variable ( y ) in the equation ( 5y + 2 = 17 ), we start by isolating ( y ).

First, subtract 2 from both sides of the equation to eliminate the constant on the left side:

[

5y + 2 - 2 = 17 - 2

]

This simplifies to:

[

5y = 15

]

Next, to solve for ( y ), divide both sides of the equation by 5:

[

\frac{5y}{5} = \frac{15}{5}

]

This gives us:

[

y = 3

]

Thus, the value of the variable ( y ) is 3.

In this context, option B (5) does not reflect the derived solution from the equation. The correct value, which is 3, comes from following the proper steps of isolating the variable by first removing the additional constant and then dividing through by the coefficient of ( y ), which is 5.

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